go - time.Millisecond * int confusion

In the below example, if the 1000's are both int's (which I think they are) why would the bottom fail to compile?

//works
time.Sleep(1000 * time.Millisecond)

//fails
var i = 1000

time.Sleep(i * time.Millisecond)

Answer

Operators

Operators combine operands into expressions.

Comparisons are discussed elsewhere. For other binary operators, the
operand types must be identical unless the operation involves shifts

or untyped constants. For operations involving constants only, see the
section on constant expressions.

Except for shift operations, if one operand is an untyped constant and
the other operand is not, the constant is converted to the type of the
other operand.

For example, using the "*" (multiplication) operator,

package main

import (
    "time"
)

func main() {

    // works - 1000 is an untyped constant
    // which is converted to type time.Duration

    time.Sleep(1000 * time.Millisecond)

    // fails - v is a variable of type int
    // which is not identical to type time.Duration
    var v = 1000
    // invalid operation: i * time.Millisecond (mismatched types int and time.Duration)
    time.Sleep(v * time.Millisecond)
}