Sunday, 1 October 2017

javascript - Ajax request returns 200 OK, but an error event is fired instead of success



I have implemented an Ajax request on my website, and I am calling the endpoint from a webpage. It always returns 200 OK, but jQuery executes the error event. I tried a lot of things, but I could not figure out the problem. I am adding my code below:



jQuery Code



var row = "1";
var json = "{'TwitterId':'" + row + "'}";

$.ajax({
type: 'POST',
url: 'Jqueryoperation.aspx?Operation=DeleteRow',
contentType: 'application/json; charset=utf-8',
data: json,
dataType: 'json',
cache: false,
success: AjaxSucceeded,
error: AjaxFailed
});

function AjaxSucceeded(result) {
alert("hello");
alert(result.d);
}
function AjaxFailed(result) {
alert("hello1");
alert(result.status + ' ' + result.statusText);
}



C# code for JqueryOpeartion.aspx



protected void Page_Load(object sender, EventArgs e) {
test();
}
private void test() {
Response.Write("");
}



I need the ("Record deleted") string after successful deletion. I am able to delete the content, but I am not getting this message. Is this correct or am I doing anything wrong? What is the correct way to solve this issue?


Answer



jQuery.ajax attempts to convert the response body depending on the specified dataType parameter or the Content-Type header sent by the server. If the conversion fails (e.g. if the JSON/XML is invalid), the error callback is fired.






Your AJAX code contains:



dataType: "json"



In this case jQuery:




Evaluates the response as JSON and returns a JavaScript object. […]
The JSON data is parsed in a strict manner; any malformed JSON is
rejected and a parse error is thrown. […] an empty response is also
rejected; the server should return a response of null or {} instead.





Your server-side code returns HTML snippet with 200 OK status. jQuery was expecting valid JSON and therefore fires the error callback complaining about parseerror.



The solution is to remove the dataType parameter from your jQuery code and make the server-side code return:



Content-Type: application/javascript

alert("Record Deleted");


But I would rather suggest returning a JSON response and display the message inside the success callback:




Content-Type: application/json

{"message": "Record deleted"}

No comments:

Post a Comment

casting - Why wasn't Tobey Maguire in The Amazing Spider-Man? - Movies & TV

In the Spider-Man franchise, Tobey Maguire is an outstanding performer as a Spider-Man and also reprised his role in the sequels Spider-Man...