I got this error:
UnicodeDecodeError: 'utf-8' codec can't decode byte 0xff in position: 0, invalid start byte
I found this solution:
>>> b"abcde".decode("utf-8")
from here:
Convert bytes to a Python string
But how do you use it if a) you don’t know where the 0xff is and/or b) you need to decode a file object? What is the correct syntax / format?
I am parsing through a directory, so I tried going through the files one at a time. (NOTE: This won't work when the project gets larger!!!)
>>> i = "b'0xff'"
>>> with open('firstfile') as f:
... g=f.readlines()
...
>>> i in g
False
>>> 0xff in g
False
>>> '0xff' in g
False
>>> b'0xff' in g
False
>>> with open('secondfile') as f:
>>> with open('thirdfile') as f:
... g = f.readlines()
...
Traceback (most recent call last):
File "", line 2, in
File "/usr/local/lib/python3.4/codecs.py", line 313, in decode
(result, consumed) = self._buffer_decode(data, self.errors, final)
UnicodeDecodeError: 'utf-8' codec can't decode byte 0xff in position 0: invalid start byte
So if this is the right file, and if I can't open it with Python (I put it in sublime text, found nothing) how do I decode, or encode, this?
Thanks.
Answer
You have a number of problems:
i = "b'0xff'"
Creates a string of 7 bytes, not a single 0xFF byte.i = b'\xff'
ori = bytes([0xff])
is the correct method.open
defaults to decoding files using the encoding returned bylocal.getpreferredencoding(False)
. Open in binary mode to get raw un-decoded bytes:open('firstfile','rb')
.g=f.readlines()
returns a list of lines.i in g
checks for an exact match of the content of i to the content of a line in the line list.- Use meaningful variable names!
Instead:
byte = b'\xff'
with open('firstfile','rb') as f:
file_content = f.read()
if byte in file_content:
...
To decode a file, you need to know it's correct encoding and provide it when you open the file:
with open('firstfile',encoding='utf8') as f:
file_content = f.read()
If you don't know the encoding, the 3rd party chardet
module can help you guess.
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