In my code, I have a condition that looks like
if (variable !== null && variable !== undefined) {
}
But instead of doing it in two steps, i.e checking if it is not defined and not null. Is there a one step checking that replaces this check.
Answer
A variable cannot be both null
and undefined
at the same time. However, the direct answer to your question is:
if (variable != null)
One =
, not two.
There are two special clauses in the "abstract equality comparison algorithm" in the JavaScript spec devoted to the case of one operand being null
and the other being undefined
, and the result is true
for ==
and false
for !=
. Thus if the value of the variable is undefined
, it's not != null
, and if it's not null, it's obviously not != null
.
Now, the case of an identifier not being defined at all, either as a var
or let
, as a function parameter, or as a property of the global context is different. A reference to such an identifier is treated as an error at runtime. You could attempt a reference and catch the error:
var isDefined = false;
try {
(variable);
isDefined = true;
}
catch (x) {}
I would personally consider that a questionable practice however. For global symbols that may or may be there based on the presence or absence of some other library, or some similar situation, you can test for a window
property (in browser JavaScript):
var isJqueryAvailable = window.jQuery != null;
or
var isJqueryAvailable = "jQuery" in window;
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