Sunday, 29 April 2018
if statement - IF/ELSE to echo image in PHP
Answer
Answer
I am trying to echo a specific image based on the results of a IF/ELSE statement, however I can't quite work out the phrasing of the IF/ELSE statement. I'm a relative newbie to PHP, so I'm sure that it's just a little error in the code somewhere, but if anyone could offer any assistance, I'd be grateful!
I'm currently at the stage below:
$fresh = if ($reviews['reviews']['freshness']) = 'fresh' {
echo '';
} else {
echo '';
}
?>
foreach($reviews['reviews'] as $rv){
if ($tmp++ < 10);
echo $fresh;
echo '' . $rv['quote'] . ' ';
}
?>
Thank you!
Answer
you cant assign if statement to a value.
if ($reviews['reviews']['freshness'] == 'fresh') {
echo '';
} else {
echo '';
}
another prettier way would be:
if ($reviews['reviews']['freshness'] == 'fresh') {
$image = "fresh";
}
else {
$image = "rotten";
}
echo '';
Subscribe to:
Post Comments (Atom)
casting - Why wasn't Tobey Maguire in The Amazing Spider-Man? - Movies & TV
In the Spider-Man franchise, Tobey Maguire is an outstanding performer as a Spider-Man and also reprised his role in the sequels Spider-Man...
-
The whole error output being: LNK2019 unresolved external symbol wWinMain referenced in function "int __cdecl __scrt_common_main_seh(vo...
-
I have come across CORS issues multiple times and can usually fix it but I want to really understand by seeing this from a MEAN stack paradi...
-
I recently used canvas to conert images to webp, using : const dataUrl = canvas.toDataURL('image/webp'); But this takes a lots of ti...
No comments:
Post a Comment