Parse error: syntax error, unexpected 'if' (T_IF) in StatusIG.php on line 25
I really dont see any problem in my code, why this is happening, please help. Im a beginner in PHP
my LINE 25 is >> if($status == 0)
$accountdb_ip = "ip"; //Accountserver-IP
$accountdb_login = "acc"; //Accountserver-Loginname
$accountdb_pw = "psw"; //Accountserver-Passwort
$db_ip = "ip"; //DB-Server-IP
$db_login = "acc"; //DB-Server-Loginname
$db_pw = "psw"; //DB-Server-Passwort
$con = mysql_connect($db_ip, $db_login, $db_pw);
$con_account = mysql_connect($accountdb_ip, $accountdb_login, $accountdb_pw);
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
$name = mysql_real_escape_string($_GET["name"], $con);
$result_id = mysql_query("SELECT * FROM player.player WHERE name='".$name."' LIMIT 1", $con);
$player_acc_id = mysql_result($result_id, 0, "account_id");
$result = mysql_query("SELECT * FROM account.account WHERE id='".$player_acc_id."'", $con);
$status = mysql_result($result, 0, "raiguard")
if($status == 0)
{echo "0";}
elseif($status == 1)
{echo "1";}
elseif($status == 2)
{echo "2";}
mysql_close($con);
mysql_close($con_account);
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